Respuesta :

bhadelsimron19

Answer:

second option is correct

Step-by-step explanation:

[tex]\frac{x^0y^-3}{x^2y^-1}[/tex]

=x^0-2 *y-3-(-1)

=x^-2*y^-3+1

=x^-2*y-2

=[tex]\frac{1}{x^2y^2}[/tex]

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