Answer:
Step-by-step explanation:
Use the exponential function
[tex]v(t)=a(b)^t[/tex] where a is the initial value of the car, b is the rate of decay, and t is the time in years. For us, a = 18000, b = (1 - .15), so the model for this car is:
[tex]v(t)=18000(.85)^t[/tex] We can use this model now to find the value, v(t), of the car after 3 years has gone by (from 2006 to 2009 is 3 years):
[tex]v(t)=18000(.85)^3[/tex] and simplifying a bit:
v(t) = 18000(.614125) so
v(t) = 11054.25
Round however you need to.
