Respuesta :

The Answer is:

C.) (x+2)(x+3)

AJ421

Answer:

(x-2)(x+3)

Step-by-step explanation:

1. Start by setting up the synthetic division. The numbers 1, -4, -11, and 30 go on the inside on the division. To get the number on the outside, set x-5 equal to 0. solve and get 5.

2. bring the one down. multiply the one and the five and place the number you get underneath the -4 in the next column. From there, add the two numbers in the column.

3. After adding those two numbers, put the number you get (which should be 1) directly below the 5. Now multiply that number and the 5 again.

4. Repeat these steps until you fill the spaces under the next two columns. If you do it correctly, the number at the bottom of the very last column should be 0. This zero is known as the remainder. The remainder is not needed to complete this problem.

 Now that you have finished synthetic division, it is time to set up the new equation you got.

5. The 1 on the bottom left will be your [tex]x^{2}[/tex] value, the next 1 will be your x value, and the -6 will be your c. You should get the equation [tex]x^{2} + x -6[/tex]

6. From here, factor the polynomial. The factors must add up to the middle value (1) and multiple to c (-6). The factors -2 and 3 add up to 1 and multiply to -6

Therefore, your answer will be (x-2)(x+3)

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