help me out pleaseeee

Answer:
The correct option is (b).
Step-by-step explanation:
The solution of the given polynomial is :
[tex](-\dfrac{1}{3},4)[/tex]
x = 1/3 and y = -4
i.e.
Sum of roots = (1/3-4) = -11/3
Product of roots = (1/3)(-4) = -4/3
The quadratic equation is as follows :
[tex]x^2+(\text{sum of roots})x+\text{Product of roots}=0[/tex]
Put all the values,
[tex]x^2+\dfrac{-11}{3}x+\dfrac{-4}{3}=0\\\\3x^2-11x-4=0[/tex]
So, the correct option is (b).