Answer:
[tex]1.74molNO_2[/tex]
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to perform mole-mass relationships by using the molar mass of the involved substance, in this case NO2, which is 46.0 g/mol; then we just set up a conversion factor like the one shown below:
[tex]80g*\frac{1mol}{46g}\\\\1.74molNO_2[/tex]
Regards!