Answer: A volume of 10.66 mL of 1.5 M H is required to exactly neutralize 20. milliliters of a 0.8 M KOH solution.
Explanation:
Given: [tex]M_{1}[/tex] = 1.5 M, [tex]V_{1}[/tex] = ?
[tex]V_{2}[/tex] = 20 mL, [tex]M_{2}[/tex] = 0.8 M
Formula used to calculate the volume is as follows.
[tex]M_{1}V_{1} = M_{2}V_{2}[/tex]
Substitute the values into above formula as follows.
[tex]M_{1}V_{1} = M_{2}V_{2}\\1.5 M \times V_{1} = 0.8 M \times 20 mL\\V_{1} = 10.66 mL[/tex]
Thus, we can conclude that a volume of 10.66 mL of 1.5 M H is required to exactly neutralize 20. milliliters of a 0.8 M KOH solution.
