Given: Volume of the cone is 83.7 m³
We know that:
[tex]\bigstar \ \ \boxed{\sf{\textsf{Volume of cone is given by} : \dfrac{\pi r^2h}{3}}}[/tex]
where r is the radius of the cone and h is the height of the cone
Given: Height of the cone = 5m
Substituting the values in the formula, we get:
[tex]\sf{\implies \dfrac{\pi r^2(5)}{3} = 83.7}[/tex]
[tex]\sf{\implies \pi r^2 = 83.7 \times \dfrac{3}{5}}[/tex]
[tex]\sf{\implies \pi r^2 = 83.7 \times 0.6}[/tex]
[tex]\sf{\implies \pi r^2 = 50.22}[/tex]
[tex]\sf{\implies r^2 = \dfrac{50.22}{\pi}}[/tex]
[tex]\sf{\implies r^2 = 16}[/tex]
[tex]\sf{\implies r = 4}[/tex]
We know that : Diameter is two times the radius
⇒ Diameter of the Cone is 8 meters
