Answer:
The maximum amplitude power is 1.12 W
Explanation:
Given;
length of each side of the square, L = 18 cm = 0.18 m
angular frequency, f = 60 Hz
magnetic field, B = 0.3 T
resistance of the loop, R = 12 ohm
The area of the loop, A = L² = 0.18 m x 0.18 m = 0.0324 m²
The angular speed, ω = 2πf = 2π x 60 = rad/s = 377.04 rad/s
The maximum value of emf induced;
[tex]E_{max} = NBA \omega\\\\where; \\N \ is \ number \ of \ turns\\\\E_{max} = (1) \times 0.3 \times 0.0324 \times 377.04\\\\E_{max} = 3.665 \ V[/tex]
The maximum amplitude power is calculated as;
[tex]Power = \frac{(E_{max})^2 }{R} \\\\Power = \frac{(3.665)^2}{12} \\\\Power = 1.12 \ W[/tex]
