Answer:
The solution for the system of right triangles are, respectively: [tex]a = 2\sqrt{6}[/tex], [tex]b = 4\sqrt{3}[/tex], [tex]c = 4\sqrt{6}[/tex], [tex]d = 6\sqrt{2}[/tex]
Step-by-step explanation:
By Geometry, we get the following equivalencies:
[tex]a = 2\sqrt{6}[/tex] (45 - 45 - 90 Theorem)
[tex]b = \sqrt{2}\cdot (2\sqrt{6})[/tex] (45 - 45 - 90 Theorem)
[tex]b = 4\sqrt{3}[/tex]
[tex]c = \frac{2\sqrt{6}}{\frac{1}{2} }[/tex] (30 - 60 - 90 Theorem)
[tex]c = 4\sqrt{6}[/tex]
[tex]d = \frac{2\sqrt{6}}{\frac{\sqrt{3}}{3} }[/tex] (30 - 60 - 90 Theorem)
[tex]d = 6\sqrt{2}[/tex]
