A local water park has two types of season passes. Plan A costs a one-time fee of $144 for admission plus $10 for parking every trip. Plan B costs a one-time fee of $48 for parking plus $22 for admission every trip. How many visits must a person make for plan A and plan B to be equal in value?

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Plan A = 10x + 144
Plan B = 48 + 22y
Equate them
10x + 144 = 22y + 48
22y - 10x = 144 - 48
22y - 10x = 96
divide by 2
11y - 5x = 48
What I did was just use trial and error at this point.
11(8) - 5(8) = 48

8 visits must a person make for plan A to plan B.

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Parrain Parrain · Answer 2 · 2021-09-23T12:22:56+02:00

The person must make 8 trips for Plan A and B to be equal.

Plan A will cost $144 and then $10 for every parking. Assuming the number of trips is x, the expression would be:

= One time fee + (Fee per parking x number of trips)

= 144 + 10x

Plan B will cost $48 then parking of $22. Expression will be:

= 48 + 22x

To find out the number of trips where the cost will be equal, equate the two:

144 + 10x = 48 + 22x

144 - 48 = 22x - 10x

96 = 12x

x = 96 / 12

x = 8 trips

The person must therefore make 8 trips for Plan A and B to be equal.

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