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Kumar bought some mangoes. The price of each mango () is found to be 6 more than the total number of mangoes bought by him and the total amount paid for all the mangoes is 280. Represent the situation mathematically and find the total number of mangoes bought by Kumar.​

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Answer:

Price = 20, Amount = 14

Step-by-step explanation:

A = Amount of Mangoes

P = Price for 1 Mango

P = A + 6

280 = P * A

insert A+6 for P

280 = (A+6) * A

280 = 6A + A²

280=1*a^2+6*a  | Vertausche beide Seiten der Gleichung.

1*a^2+6*a=280  | quadratische Ergänzung: ergänze auf beiden Seiten (3)^2

1*a^2+6*a+(3)^2=3^2+280  | Rechne 3 hoch 2 aus.

1*a^2+6*a+(3)^2=9+280  | addiere 9 und 280

1*a^2+6*a+(3)^2=9+280  | Fasse die rechte Seite mit Hilfe der binomischen Formel zusammen.

1*(1*a+(3))^2=289  | Auf beiden Seiten Quadratwurzel ziehen.

1*a+(3)=+-*289^0.5  

1*a_1+(3)=289^0.5  

1*a_1+3=289^0.5  | Ziehe die Wurzel aus 289

1*a_1+3=17  | -3

1*a_1=14  

The total number of mangoes bought by Kumar are 14.

What is mathematical equation?

"An equation is a mathematical statement with an 'equal to' symbol between two expressions that have equal values is called mathematical equation. For example, 3x + 5 = 15. There are different types of equations like linear, quadratic, cubic, etc."

We have,

Total amount for mangoes(P) =  280

Price of one mango is equal to 6 more than the total number of mangoes (A) i.e., P = A+6

By using mathematical equation from the question

P×A = 280.....(1)

Substitute P = A+6 in equation (1)

⇒ (A+6) × A = 280

⇒[tex]A^{2}+6A =280[/tex]

Add [tex]3^{2}[/tex] on both sides of above equation

⇒[tex]A^{2}+6A+3^{2} = 280+3^{2}[/tex]

⇒[tex]A^{2}+2.(1)(3A)+3^{2} =289[/tex]          (∵ [tex](a+b)^{2} = a^{2}+2ab+b^{2}[/tex])

⇒[tex](A+3)^{2} =289[/tex]

⇒[tex]A+3 = \sqrt{289}[/tex]

⇒[tex]A=17-3[/tex]

⇒[tex]A=14[/tex]

Hence, The total number of mangoes bought by Kumar are 14.

Learn more about mathematical equation here

https://brainly.com/question/15389595

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