SmartVPenguin
contestada

A 50.0 kg object is moving east at an unknown velocity when it collides with a 60.0 kg stationary object. After collision, the 50.0 kg object is traveling at a velocity of 6.0 m/s 50.0degree N of E and the 60.0 kg object is traveling at a velocity of 6.3 m/s 38degree S of E.

What was the velocity of the 50.0 kg object before collision?

p=m•v is the formula.

Respuesta :

mickymike92

Based on the principle of conservation of momentum,  the velocity of the 50.0 kg object before collision was 13.56 m/s.

What was the velocity of the 50.0 kg object before collision?

The principle of conservation of momentum states that:

  • momentum before collision = momentum after collision
  • Momentum = mass * velocity

Momentum before collision:

Velocity of 50.0 kg object = v m/s

Momentum of 50.0 kg object = 50 * v

Momentum after collision:

Velocity of the 50.0 kg object = 6.0 m/s 50.0degree N of E

Velocity of the 60.0 kg object = 6.3 m/s 38degree S of E.

Momentum of 50.0 kg object = 50 * 6 = 300 kgm/s

Momentum of 50.0 kg object = 60 * 6.3 = 378 kgm/s

Total momentum after collision = 678 kgm/s

From the principle of conservation of momentum:

50 kg * v = 678 kgm/s

v = 678 kgm/s / 50 kg

velocity, v = 13.56 m/s

Therefore, the velocity of the 50.0 kg object before collision was 13.56 m/s.

Learn more about conservation of momentum at: https://brainly.com/question/7538238

Otras preguntas