Respuesta :
position in the sequence triangular number relation
1 1 1 = 1*(1+1)/2
2 3 3 = 2(2+1)/2
3 6 6 = 3(3+1)/2
4 10 10 = 4(4+1)/2
5 15 15= 5(5+1)/2
Call n the position in the sequence, then the triangular number is: n(n+1)/2
1 1 1 = 1*(1+1)/2
2 3 3 = 2(2+1)/2
3 6 6 = 3(3+1)/2
4 10 10 = 4(4+1)/2
5 15 15= 5(5+1)/2
Call n the position in the sequence, then the triangular number is: n(n+1)/2
direct variation is y = kx where y would be the value of the number and x would be its position in the sequence, k is a constant
so for consecutive values y/x would be a constant k
In this case its not true becuse for example 3/1 = 3 and 6/3 = 2
so there is no direct variation here.