Answer:
h = 24.25 feet
Step-by-step explanation:
Xavier shoots a basketball in which the height, in feet, is modeled by the equation.
[tex]h(t) = -4t^2+10t +18[/tex] ....(1)
For maximum height,
Put dh/dt=0
So,
[tex]\dfrac{dh}{dt}=\dfrac{d}{dt}(-4t^2+10t +18)\\\\=-8t+10[/tex]
So,
-8t = -10
t =1.25s
Put t = 1.25 s in equation (1)
[tex]h(t) = -4(1.25)^2+10(1.25) +18\\\\=24.25\ feet[/tex]
So, the maximum height of the basketball is equal to 24.25 feet.
