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Find the coefficient of the squared term in the simplified form for the second derivative, f "(x) for f(x) = (x³ + 3x² + 3)(3x³ − 6x² − 8x + 1) . Use the hyphen symbol, -, for negative values.

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f(x) = (x³ + 3x² + 3)(3x³ − 6x² − 8x + 1)
f(x) = 3x⁶ - 6x⁵ - 8x⁴ + x³ + 9x⁵ - 18x⁴ - 24x³ + 3x² + 9x³ - 18x² - 24x + 3
f(x) = 3x⁶ + 3x⁵ -26x⁴ - 14x³ - 15x² -24x + 3
f'(x) = 18x⁵ + 15x⁴ - 104x³ - 30x - 24
f''(x) = 90x⁴ + 60x³ - 112x² - 30

Coefficient of x² in f''(x) = -112

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