Answer:
[tex]U_x = \frac{1}{2} kx^2[/tex]
Explanation:
Find the image uploaded for the chart.
The energy stored in a stretched elastic material is known as elastic potential energy. Mathematically this energy is expressed as follows;
[tex]U_x = \frac{1}{2} fx\\\\where ;\\\\f = kx\\\\U_x = \frac{1}{2}kx^2[/tex]
The terms are defined as follows;
f is the load applied to the elastic material (N)
k is the spring constant (N/m)
x is the extension of the material (m)
Ux is the elastic potential energy (J)
