Answer:
The correct answer is "[tex]\frac{2}{7}[/tex]".
Step-by-step explanation:
According to the question,
Number of students,
= 35
A ! mid term A,
[tex]n(A) = 20[/tex]
B : final A,
[tex]n(B) = 13[/tex]
Didn't start,
[tex]n(A^c \cap B^c) = 12[/tex]
Now,
⇒ [tex]n(A \cup B)=35-12[/tex]
[tex]=23[/tex]
then,
⇒ [tex]n(A \cup B)=20+13-23[/tex]
[tex]=10[/tex]
hence,
The probability will be:
⇒ [tex]P(A \cap B)=\frac{10}{35}[/tex]
⇒ [tex]=\frac{2}{7}[/tex]
