A gas has an initial volume of 212 cm^3 at a temperature of 293 K and a pressure of 0.98 atm. What is the final pressure of the gas if the volume decreases to 196 cm^3 and the temperature of the gas increases to 308 K?

a. 0.86 atm
b. 0.95 atm
c. 1.0 atm
d. 1.1 atm

Respuesta :

For this we use general equation for gases. Our variables represent:

p- pressure
v-volume
t- temperature

P1V1/T1 = P2V2/T2

in this equation we know:
P1,V1 and T1, T2 and V2. 
We have one equation and 1 unknown variable.

P2 = T2P1V1/T1V2 = 1.1atm

Answer:

For this we use general equation for gases. Our variables represent:

p- pressure

v-volume

t- temperature

P1V1/T1 = P2V2/T2

in this equation we know:

P1,V1 and T1, T2 and V2.  

We have one equation and 1 unknown variable.

P2 = T2P1V1/T1V2 = 1.1atm

Explanation:

the guy above me is VERY correct