Respuesta :
T = -0.005x^2 + 0.45x + 125
T = 132 => -0.005x^2 + 0.45x + 125 = 132
=> -0.005x^2 + 0.45x +125 -132 = 0
=> -0.005x^2 + 0.45x - 7 = 0
Discriminant: b^2 - 4ac = (0.45)^2 - 4( - 0.005)(-7) = 0.2025 - 0.14 = 0.0625
Discriminant > 0 => the equation has two real and different solutions.
Answer: yes
T = 132 => -0.005x^2 + 0.45x + 125 = 132
=> -0.005x^2 + 0.45x +125 -132 = 0
=> -0.005x^2 + 0.45x - 7 = 0
Discriminant: b^2 - 4ac = (0.45)^2 - 4( - 0.005)(-7) = 0.2025 - 0.14 = 0.0625
Discriminant > 0 => the equation has two real and different solutions.
Answer: yes
Answer: The answer saying YES, is WRONG, the CORRECT ANSWER IS NO.