Calculate the area of triangle ABC with altitude CD, given A (−3, −4), B (−6, 2), C (0, 0), and D (−4, −2). (5 points)

Question 8 options:

1)

14 square units

2)

15 square units

3)

18 square units

4)

20 square units

Respuesta :

Answer: 2) 15 square units

Step-by-step explanation:

The area of the triangle is 15 square units if the triangle ABC with altitude CD, given A (-3, -4), B (-6, 2), C (0, 0), and D (-4, -2) which is correct option (2)

What is the distance between two points?

The distance between two points is defined as the length of the line segment between two places represents their distance. Most significantly, segments that have the same length are referred to as congruent segments and the distance between two places is always positive.

The formula of distance between two points is P(x₁, y₁) and Q(x₂, y₂) is given by: d (P, Q) = √ (x₂ – x₁)² + (y₂ – y₁) ².

Given that a triangle ABC with altitude CD.

The coordinates for the triangle are A (-3, -4), B (-6, 2), C (0, 0), and D (-4, -2)

Given that the distance between C and D will be the height of the triangle

Since, the distance between the points by using the distance formula:

= √ (x₂ – x₁)² + (y₂ – y₁) ².

height = √ (-4 – 0)² + (-2 – 0) ²

height = √20

base = √45

Area of triangle = (1/2)base x height

Area of triangle = (1/2)√20×√45

Area of triangle = (1/2)30

Area of triangle = 15 square units

Hence, the area of the triangle is 15 square units if the triangle ABC with altitude CD

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