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A man leaves the town of Elmsville at 8:00 am and drives to Oak City at a constant rate of 50 miles per hour. Two hours later, a woman leaves Elmsville following the same route to Oak City. The man and woman arrive in Oak City at 3:00 p.m. What was the rate of the woman

Respuesta :

Answer: 70 mph

Step-by-step explanation:

Given

A man leaves the town of Elmsville at 8:00 am and reach oak city at 3 Pm

Rate of driving is 50 miles per hour

time taken by man [tex]t=7\ hr[/tex]

Woman leaves 2 hour later and reach by 3 Pm, so time taken is [tex]5\ hr[/tex]

Distance traveled by both the person is same

[tex]\therefore 50\times 7=v\times 5\quad[v=\text{rate of woman}]\\\\\Rightarrow v=\dfrac{50\times 7}{5}\\\\\Rightarrow v=70\ mph[/tex]

Thus , the rate of woman is 70 miles per hour.

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