Respuesta :

sreedevi102

Answer:

option b) -2/5

Step-by-step explanation:

Using the rule :

             [tex]\sqrt[3]{a^3} = (a^3)^{\frac{1}{3}} = a[/tex]

             [tex]\sqrt[n]{-x} = - \sqrt[n]{x} , if \ n \ is \ odd[/tex]

[tex]\sqrt[3]{-\frac{8}{125}} = \sqrt[3]{-\frac{2 \times 2 \times 2}{5 \times 5 \times 5}} = -\frac{2}{5}[/tex]

Answer:

[tex]\sqrt[3]{-\frac{8}{125} }[/tex]

  • [tex]-\sqrt[3]{2^3} /\sqrt[3]{5^3}[/tex]
  • [tex]-2/\sqrt[3]{5^3}[/tex]
  • [tex]-\frac{2}{5}[/tex]

So, your answer is B) - 2/5

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hope it helps...

have a great day!!

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