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Reflect shape A in the line x = -2

Answer: Check out the diagram below
The reflected image is shown in red.
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Explanation:
Draw a vertical line through -2 on the x axis. This is the mirror line.
Now focus on the upper right corner of the figure, which is at (-3, -1). Notice how the horizontal distance from this corner point to the mirror line is exactly 1 unit. If we move another 1 unit to the right, then we'll arrive at (-1,-1) which is where the reflected point lands or ends up.
In short, the upper right corner point (-3,-1) reflects over x = -2 to land on (-1,-1)
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As another example, the upper left corner point (-5, -1) will move exactly 4 spaces to the right to get to the mirror line. Then we move another 4 spaces to the right to get to (2,-1).
So the upper left corner (-5,-1) will ultimately move to (2,-1) after the reflection over x = -2.
Apply these steps to the other corner points and you'll end up with what is shown below.
Take note that a point like A(-5,-1) moves to A'(1,-1), and similar to the other points as well. Also, notice that when going from A to B to C, etc we are moving clockwise. We move counterclockwise when going from A' to B' to C' etc. Reflections always swap the orientation.
Transformation involves changing the position of a shape.
The coordinates of the image are:
[tex]\mathbf{A '= (1,1)}[/tex] [tex]\mathbf{B' = (-1,-1)}[/tex] [tex]\mathbf{C' = (-1,-4)}[/tex] [tex]\mathbf{D' = (0,-4)}[/tex]
[tex]\mathbf{E' = (0,-3)}[/tex] [tex]\mathbf{F = (1,-3)}[/tex]
The vertices of the shape are:
[tex]\mathbf{A = (-5,-1)}[/tex]
[tex]\mathbf{B = (-3,-1)}[/tex]
[tex]\mathbf{C = (-3,-4)}[/tex]
[tex]\mathbf{D = (-4,-4)}[/tex]
[tex]\mathbf{E = (-4,-3)}[/tex]
[tex]\mathbf{F = (-5,-3)}[/tex]
The rule of reflection across line x =-2 is:
[tex]\mathbf{(x,y)=(-x -4,y)}[/tex]
So, we have:
[tex]\mathbf{A '= (5 - 4,-1) = (1,-1)}[/tex]
[tex]\mathbf{B' = (3-4,-1) = (-1,-1)}[/tex]
[tex]\mathbf{C' = (3-4,-4) = (-1,-4)}[/tex]
[tex]\mathbf{D' = (4-4,-4) = (0,-4)}[/tex]
[tex]\mathbf{E' = (4-4,-3) = (0,-3)}[/tex]
[tex]\mathbf{F = (5-4,-3) = (1,-3)}[/tex]
So, the coordinates of the image are:
[tex]\mathbf{A '= (1,-1)}[/tex]
[tex]\mathbf{B' = (-1,-1)}[/tex]
[tex]\mathbf{C' = (-1,-4)}[/tex]
[tex]\mathbf{D' = (0,-4)}[/tex]
[tex]\mathbf{E' = (0,-3)}[/tex]
[tex]\mathbf{F = (1,-3)}[/tex]
See attachment for the image of the transformations
Read more about transformations at:
https://brainly.com/question/11709244