A machine cuts dry wall screws with specifications such that the length of each screw is 1.25 inches with an allowable margin of error of 0.02 inches. Use this information to complete each statement.

Answer:
[tex](a)\ x = 1.25 \± 0.02[/tex]
[tex](b)[/tex]
[tex]Minimum = 1.23in[/tex]
[tex]Maximum = 1.27in[/tex]
Step-by-step explanation:
Given
[tex]L = 1.25in[/tex] --- Length
[tex]E=0.02in[/tex] -- Margin of error
Solving (a): The equation of the length
This is calculated as:
[tex]x = L \± E[/tex]
So, we have:
[tex]x = 1.25 \± 0.02[/tex]
Solving (b): The range of value of x
In (a), we have:
[tex]x = 1.25 \± 0.02[/tex]
Split:
[tex]x = 1.25 - 0.02[/tex] [tex]x = 1.25 + 0.02[/tex]
Solve for x
[tex]x = 1.23[/tex] [tex]x = 1.27[/tex]
So, we have:
[tex]Minimum = 1.23in[/tex]
[tex]Maximum = 1.27in[/tex]