Answer:
The correct answer will be "2".
Explanation:
Given:
Heat generated through wall,
= 15000 kJ/h
= [tex]\frac{15000}{3600}[/tex]
= [tex]4.17 \ KW[/tex]
Heat generated by bulbs,
= [tex]10(100) \ W[/tex]
= [tex]1000[/tex]
= [tex]1 \ KW[/tex]
Heat generated by people,
= [tex]40(360) \ KJ/h[/tex]
= [tex]\frac{14400}{3600}[/tex]
= [tex]4 \ KW[/tex]
Heat removed by 1 AC,
= 5 KW
Now,
The total increase in heat will be:
= [tex]4+1+4.17[/tex]
= [tex]9.17 \ KW[/tex]
hence,
The required number of AC will be:
⇒ [tex]5n=9.17[/tex]
⇒ [tex]n=\frac{9.17}{5}[/tex]
⇒ [tex]=1.83[/tex]
0r,
⇒ [tex]2[/tex]