Answer: The concentration of a solution made by combining 52 grams of [tex]NaCH_{3}COO^{-}[/tex] with 150 mL of water is 4.22 M.
Explanation:
Given: Mass = 52 grams
Volume = 150 mL (1 mL = 0.001 L) = 0.150 L
Molarity is the number of moles of a substance present in liter of a solution.
And, moles is the mass of a substance divided by its molar mass.
Hence, moles of [tex]NaCH_{3}COO^{-}[/tex] (molar mass = 82.034 g/mol) is as follows.
[tex]Moles = \frac{mass}{molar mass}\\= \frac{52 g}{82.034 g/mol}\\= 0.633 mol[/tex]
Therefore, concentration of given solution is as follows.
[tex]Molarity = \frac{moles}{Volume(in L)}\\= \frac{0.633 mol}{0.150 L}\\= 4.22 M[/tex]
Thus, we can conclude that the concentration of a solution made by combining 52 grams of [tex]NaCH_{3}COO^{-}[/tex] with 150 mL of water is 4.22 M.
