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a 10 kg box is pulled across an ice rink for a distance of 50m. it is pulled with a constant force of 10 N on a rope angled at 60° to the horizontal. How much work is done on the box? (A) 50 ) (B) 100 ) (C) 250 ) (D) 500)​

Respuesta :

Lanuel

Answer:

(C) 250

Explanation:

Given the following data;

Mass = 10 kg

Distance = 50 m

Force applied = 10 N

Angle = 60°

To find the work done on the box, we would first of all find the horizontal component of the force applied.

[tex] Horizontal force, Fx = mgCosd[/tex]

Where;

Fx represents the horizontal force.

m is the mass of an object.

g is the acceleration due to gravity.

d is the angle of inclination (theta).

mg = weight = 10 N

Substituting into the equation, we have;

[tex] Fx = 10 * Cos60 [/tex]

[tex] Fx = 125 * 0.5 [/tex]

Fx = 5 Newton

Next, we find the work done.

Mathematically, workdone is given by the formula;

[tex] Workdone = force * distance[/tex]

Substituting into the formula, we have;

[tex] Workdone = 5 * 50 [/tex]

Workdone = 250 Nm

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