Answer:
4.76 mol / L
Explanation:
The process that takes place is:
- Sc₂(C₂O₄)₃ → 2Sc⁺³ + 3C₂O₄⁻²
Assuming we have 1 L of the solution, we would have 2.38 moles of Sc₂(C₂O₄)₃.
We then convert 2.38 moles of Sc₂(C₂O₄)₃ into moles of Sc⁺³, using the stoichiometric coefficients:
- 2.38 mol Sc₂(C₂O₄)₃ * [tex]\frac{2molSc^{+3}}{1molSc_2(C_2O_4)_3}[/tex] = 4.76 mol Sc⁺³
Finally we calculate the concentration of scandium ion (Sc⁺³) in mol/L:
- 4.76 mol Sc⁺³ / 1 L = 4.76 mol/L
