Respuesta :

Answer:

Step-by-step explanation:

1) Vertically opposite angles are equal.

x + 30 = 180 - 2x

Add '2x' to both sides

x + 30  +2x = 180

3x + 30 = 180

Subtract 30 from both sides

3x = 180 - 30

3x = 150

 x = 150/3

x = 50

2)  Let the angle be x

It's complement angle = 90 - x

[tex]x = \frac{2}{3}(90-x)\\\\x = \frac{2}{3}*90 - \frac{2}{3}*x\\\\x =2*30 - \frac{2}{3}x\\\\x +\frac{2}{3}x = 60\\\\\frac{3}{3}x+\frac{2}{3}x=60\\\\\frac{5}{3}x =60\\\\x = 60*\frac{3}{5}\\\\x = 12*3\\x = 36[/tex]

The angles are : 36 , 54

3) Let the angle be x

It's supplement = 180 - x

[tex]x = \frac{1}{5}(180-x)\\\\x =\frac{1}{5}*180 - \frac{1}{5}x\\\\x + \frac{1}{5}x= 36\\\\\frac{5}{5}x +\frac{1}{5}x = 36\\\\\frac{6}{5}x = 36\\\\x = 36*\frac{5}{6}\\\\x = 6*5 = 30\\[/tex]

Angles are  30 , 150

4) Ratio = 7 : 3

The angles are = 7x , 3x

7x + 3x = 180

10x = 180

x = 180/10

x = 18

7x = 7 * 18 = 126

3x = 3 * 18 = 54

Angles are 126 , 54

1. Intersecting lines are lines that cross each other. When two lines intersect, the opposite angles are equal.

Given: x + 30° and 180° - 2x are vertically opposite angles

⇒   x + 30° = 180° - 2x

⇒   3x = 150°

⇒   x = 50°

2. Let the complement be : C

Given : The other angle is two third of its complement

[tex]\sf{\implies Other \ angle = \dfrac{2}{3} \times C}[/tex]

Two angles are said to be Complementary if their sum is equal to 90°

[tex]\sf{\implies C + \dfrac{2C}{3} = 90}[/tex]

[tex]\sf{\implies \dfrac{5C}{3} = 90}[/tex]

[tex]\sf{\implies 5C = 270}[/tex]

[tex]\sf{\implies C = 54}[/tex]

[tex]\sf{\implies Other \ angle = \bigg(\dfrac{2}{3} \times C\bigg) = \bigg(\dfrac{2}{3} \times 54\bigg) = 36 }[/tex]

Answer: The size of the angle which is two third of its complement is 36°

3. Let the supplement be : S

Given : The other angle is one fifth of its supplement

[tex]\sf{\implies Other \ angle = \dfrac{1}{5} \times S}[/tex]

Two angles are said to be Supplementary if their sum is equal to 180°

[tex]\sf{\implies S + \dfrac{S}{5} = 180}[/tex]

[tex]\sf{\implies \dfrac{6S}{5} = 180}[/tex]

[tex]\sf{\implies 6S = 900}[/tex]

[tex]\sf{\implies S = 150}[/tex]

[tex]\sf{\implies Other \ angle = \bigg(\dfrac{1}{5} \times S\bigg) = \bigg(\dfrac{1}{5} \times 150\bigg) = 30 }[/tex]

Answer: The size of the angle which is one fifth of its supplement is 30°

4. Two supplementary angles are in the ratio 7 : 3

Let the supplementary angles be : 7S and 3S

Two angles are said to be Supplementary if their sum is equal to 180°

⇒   7S + 3S = 180°

⇒  10S = 180°

⇒   S = 18°

First Angle : 7S = (7 × 18) = 126°

Second Angle : 3S = (3 × 18) = 54°