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Answer:
Step-by-step explanation:
1) Vertically opposite angles are equal.
x + 30 = 180 - 2x
Add '2x' to both sides
x + 30 +2x = 180
3x + 30 = 180
Subtract 30 from both sides
3x = 180 - 30
3x = 150
x = 150/3
x = 50
2) Let the angle be x
It's complement angle = 90 - x
[tex]x = \frac{2}{3}(90-x)\\\\x = \frac{2}{3}*90 - \frac{2}{3}*x\\\\x =2*30 - \frac{2}{3}x\\\\x +\frac{2}{3}x = 60\\\\\frac{3}{3}x+\frac{2}{3}x=60\\\\\frac{5}{3}x =60\\\\x = 60*\frac{3}{5}\\\\x = 12*3\\x = 36[/tex]
The angles are : 36 , 54
3) Let the angle be x
It's supplement = 180 - x
[tex]x = \frac{1}{5}(180-x)\\\\x =\frac{1}{5}*180 - \frac{1}{5}x\\\\x + \frac{1}{5}x= 36\\\\\frac{5}{5}x +\frac{1}{5}x = 36\\\\\frac{6}{5}x = 36\\\\x = 36*\frac{5}{6}\\\\x = 6*5 = 30\\[/tex]
Angles are 30 , 150
4) Ratio = 7 : 3
The angles are = 7x , 3x
7x + 3x = 180
10x = 180
x = 180/10
x = 18
7x = 7 * 18 = 126
3x = 3 * 18 = 54
Angles are 126 , 54
1. Intersecting lines are lines that cross each other. When two lines intersect, the opposite angles are equal.
Given: x + 30° and 180° - 2x are vertically opposite angles
⇒ x + 30° = 180° - 2x
⇒ 3x = 150°
⇒ x = 50°
2. Let the complement be : C
Given : The other angle is two third of its complement
[tex]\sf{\implies Other \ angle = \dfrac{2}{3} \times C}[/tex]
Two angles are said to be Complementary if their sum is equal to 90°
[tex]\sf{\implies C + \dfrac{2C}{3} = 90}[/tex]
[tex]\sf{\implies \dfrac{5C}{3} = 90}[/tex]
[tex]\sf{\implies 5C = 270}[/tex]
[tex]\sf{\implies C = 54}[/tex]
[tex]\sf{\implies Other \ angle = \bigg(\dfrac{2}{3} \times C\bigg) = \bigg(\dfrac{2}{3} \times 54\bigg) = 36 }[/tex]
Answer: The size of the angle which is two third of its complement is 36°
3. Let the supplement be : S
Given : The other angle is one fifth of its supplement
[tex]\sf{\implies Other \ angle = \dfrac{1}{5} \times S}[/tex]
Two angles are said to be Supplementary if their sum is equal to 180°
[tex]\sf{\implies S + \dfrac{S}{5} = 180}[/tex]
[tex]\sf{\implies \dfrac{6S}{5} = 180}[/tex]
[tex]\sf{\implies 6S = 900}[/tex]
[tex]\sf{\implies S = 150}[/tex]
[tex]\sf{\implies Other \ angle = \bigg(\dfrac{1}{5} \times S\bigg) = \bigg(\dfrac{1}{5} \times 150\bigg) = 30 }[/tex]
Answer: The size of the angle which is one fifth of its supplement is 30°
4. Two supplementary angles are in the ratio 7 : 3
Let the supplementary angles be : 7S and 3S
Two angles are said to be Supplementary if their sum is equal to 180°
⇒ 7S + 3S = 180°
⇒ 10S = 180°
⇒ S = 18°
First Angle : 7S = (7 × 18) = 126°
Second Angle : 3S = (3 × 18) = 54°