Problem:
Evaluate this:
[tex] \quad \quad \quad \quad \tt{f(x) = { - x}^{2} + 1} \: \: when \: \: x = - 3[/tex]
Let's try!
[tex] \quad \quad \quad \quad \tt{ ⟶f(x) = { - x}^{2} + 1}[/tex]
[tex] \quad \quad \quad \quad \tt{⟶f(-3) = {- (-3)}^{2} + 1}[/tex]
[tex] \quad \quad \quad \quad \tt{⟶ f( - 3) = { - (9) + 1}}[/tex]
[tex]\quad \quad \quad \quad \tt{⟶ f( - 3) = { - 9 + 1}}[/tex]
[tex]\quad \quad \quad \quad \tt{ ⟶f( - 3) = { -8}}[/tex]
Hence, The answer is:
[tex]\quad \quad \quad \quad \boxed{\tt{ \color{green}f( - 3) = { - 8}}}[/tex]
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#LetsStudy
