Respuesta :
Answer:
C
[tex] \sqrt{48} = \sqrt{2 \times 2 \times 2 \times 2 \times 3} \\ = \sqrt{16 \times 3} \\ = 4 \sqrt{3} [/tex]
The prime factorization to write [tex]\sqrt{48}[/tex] in the simplest form as
48 = V2 -2 -2 -2 - 3 = 4V3
What is Prime Factorization in Math?
Prime factorization of any number indicates to express that number as a product of prime numbers. A prime number exists as a number that has precisely two factors, 1 and the number itself.
We require to express 48 as the product of its prime factors as 48.
= 2 [tex]\times[/tex] 3 [tex]\times[/tex] 2 [tex]\times[/tex] 2 [tex]\times[/tex] 2.
Therefore, [tex]$\sqrt{48}=\sqrt{ (2 \times 2 \times 2 \times 2 \times 2)}[/tex]
[tex]$=4 \sqrt{3}$[/tex]
[tex]$4 \sqrt{3}$[/tex] exists in the lowest radical form.
Therefore, the correct answer is option C. 48 = V2 -2 -2 -2 - 3 = 4V3.
To learn more about Prime Factorization
https://brainly.com/question/24612438
#SPJ2