Which calculation correctly uses prime factorization to write V48 in simplest form?
A. 48 = V2 -2 -2 -2 - 3 = 2V12
B. 48 = 14 - 12 = 2/12
C. 48 = V2 -2 -2 -2 - 3 = 4V3
D. V48 = 16 - 3 = 4V3​

Respuesta :

Answer:

C

[tex] \sqrt{48} = \sqrt{2 \times 2 \times 2 \times 2 \times 3} \\ = \sqrt{16 \times 3} \\ = 4 \sqrt{3} [/tex]

The prime factorization to write [tex]\sqrt{48}[/tex] in the simplest form as  

48 = V2 -2 -2 -2 - 3 = 4V3

What is Prime Factorization in Math?

Prime factorization of any number indicates to express that number as a product of prime numbers. A prime number exists as a number that has precisely two factors, 1 and the number itself.

We require to express 48 as the product of its prime factors as 48.

= 2 [tex]\times[/tex] 3 [tex]\times[/tex] 2 [tex]\times[/tex] 2 [tex]\times[/tex] 2.

Therefore, [tex]$\sqrt{48}=\sqrt{ (2 \times 2 \times 2 \times 2 \times 2)}[/tex]

[tex]$=4 \sqrt{3}$[/tex]

[tex]$4 \sqrt{3}$[/tex] exists in the lowest radical form.

Therefore, the correct answer is option C. 48 = V2 -2 -2 -2 - 3 = 4V3.

To learn more about Prime Factorization

https://brainly.com/question/24612438

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