Answer:
Explanation:
First off, let's call the -15 degree water solution1, and the 32 degree water solution2. The formula for this is
[tex]t_f=\frac{(m_1*spheat_1*temp_1)+(m_*spheat_2*temp_2)}{(m_1*spheat_1)+(m_2*spheat_2)}[/tex]
where spheat is specific heat of water that I found to be 4182 J/(kgC). This means that we need our masses in kg and they are currently in g.
100 g = .100 kg and
220 g = .220 kg. Now we're ready to plug everything in:
[tex]t_f=\frac{(.100*4182*-15)+(.220*4182*32)}{(.100*4182)+(.220*4182)}[/tex] and
[tex]t_f=\frac{-6273+29441.28}{418.2+920.04}[/tex] and
[tex]t_f=\frac{23168.28}{1338.24}[/tex] so
[tex]t_f=17.3[/tex] °C
