Given:
The expression is:
[tex]25-10\div 2+3[/tex]
To find:
Part A: The expression using parentheses so that the expression equals 23.
Part B: The expression using parentheses so that the expression equals 3.
Solution:
Part A:
In option A,
[tex](25-10)\div 2+3=15\div 2+3[/tex]
[tex](25-10)\div 2+3=7.5+3[/tex] [Using BODMAS]
[tex](25-10)\div 2+3=10.5[/tex]
In option B,
[tex]25-10\div (2+3)=25-10\div 5[/tex]
[tex]25-10\div (2+3)=25-2[/tex] [Using BODMAS]
[tex]25-10\div (2+3)=23[/tex]
In option C,
[tex](25-10)\div (2+3)=15\div 5[/tex]
[tex](25-10)\div (2+3)=3[/tex]
In option D,
[tex]25-(10\div 2)+3=25-5+3[/tex]
[tex]25-(10\div 2)+3=28-5[/tex] [Using BODMAS]
[tex]25-(10\div 2)+3=23[/tex]
After the calculation, we have [tex]25-10\div (2+3)=23[/tex] and [tex]25-(10\div 2)+3=23[/tex].
Therefore, the correct options are B and D.
Part B: From part A, it is clear that
[tex](25-10)\div (2+3)=3[/tex]
Therefore, the correct option is C.