Answer:
(D)
Explanation:
Given :
l=3.5 m
[tex]A=5.26*10^{-6}[/tex] [tex]m^{2}[/tex]
[tex]p=1.7*10^{-8} ohm.m[/tex]
Resistance can be calculated as :
[tex]R=p\frac{l}{A} \\R=1.7*10^{-8} \frac{3.5}{5.26*10^{-6} }[/tex]
[tex]R=\frac{5.95*10^{-2} }{5.26} \\R=1.13*10^{-2}[/tex]
Resistance of the wire will be 1.1×[tex]10^{-2}[/tex] ohms
Option D is correct
