Answer:
[tex]\frac{-4x+7}{2(x-2)}[/tex]
Step-by-step explanation:
[tex]For x \neq 1 \\\frac{\frac{3}{x-1}-4}{2-\frac{2}{x-1}}=\frac{\frac{3}{x-1}-\frac{4x-4}{x-1}}{\frac{2x-2}{x-1}-\frac{2}{x-1}}=\frac{\frac{-4x+7}{x-1}}{\frac{2x-4}{x-1}}=\frac{-4x+7}{2(x-2)}[/tex]
