Answer:
[tex]y=-5x+2[/tex]
Step-by-step explanation:
Hi there!
What we need to know:
1) Determine the slope (m)
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex] where two points that the line passes through are [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex]
Plug in the given points (1,-3) and (-3,17)
[tex]=\frac{17-(-3)}{-3-1}\\=\frac{17+3}{-3-1}\\=\frac{20}{-4}\\=-5[/tex]
Therefore the slope of the line is -5. Plug this into [tex]y=mx+b[/tex]:
[tex]y=-5x+b[/tex]
2) Determine the y-intercept (b)
[tex]y=-5x+b[/tex]
Plug in one of the given points and solve for b
[tex]-3=-5(1)+b\\-3=-5+b[/tex]
Add 5 to both sides of the equation to isolate b
[tex]-3+5=-5+b+5\\2=b[/tex]
Therefore, the y-intercept of the equation is 2. Plug this back into [tex]y=-5x+b[/tex]:
[tex]y=-5x+2[/tex]
I hope this helps!