Respuesta :

theleangreenbean

Answer:

[tex]y=x+9[/tex]

Step-by-step explanation:

Hi there!

What we need to know:

  • Linear equations are typically organized in slope-intercept form: [tex]y=mx+b[/tex] where m is the slope and b is the y-intercept (the value of y when the line crosses the y-axis)
  • Perpendicular lines always have slopes that are negative reciprocals (ex. 3 and -1/3, 5/6 and -6/5, etc.)

1) Determine the slope (m)

[tex]y=-x+1[/tex]

This equation can be written as [tex]y=-1x+1[/tex]. Now, we can identify clearly that -1 is the slope of this line. Because perpendicular lines have slopes that are negative reciprocals, we know that the slope of the line we're calculating for is [tex]-(\frac{1}{-1} )[/tex], or just 1.

Plug 1 into [tex]y=mx+b[/tex] as the slope:

[tex]y=1x+b[/tex]

[tex]y=x+b[/tex]

2) Determine the y-intercept (b)

Recall that the y-intercept is the value of y when the line crosses the y-axis. It occurs when x is equal to zero.

The given point is (0,9), meaning that y is 9 when x is 0. Therefore, the y-intercept is 9. Plug this into [tex]y=x+b[/tex]:

[tex]y=x+9[/tex]

I hope this helps!

Otras preguntas