Consider the equation Cost = 4.3 + 6.89 *log(length). How should the length be increased such that the cost increases by 6.89 units? (e ≈ 2.718)

Respuesta :

Answer:

Length increased by the multiplying of e

Step-by-step explanation:

From the question we are told that:

 [tex]Cost = 4.3 + 6.89 *log(length)[/tex]

Therefore cost increase by 6.89 is given as

 [tex]Cost' = 4.3 + 6.89 *log(length)+6.89[/tex]

 [tex]Cost' = 4.3 + 6.89 (log(length)+1)[/tex]

Since

 [tex]log_ee=1[/tex]

Therefore

 [tex]Cost' = 4.3 + 6.89 (log(length)+log_ee)[/tex]

Since

 [tex]log(ab)=log a+log b[/tex]

Therefore

 [tex]4.3+6.89(log Length*e)[/tex]

Therefore

Length increased by the multiplying of e

Given:

[tex]\to \bold{Cost = 4.3 + 6.89 * \log(length)}[/tex]

To find:

The length is increased to 6,89 units in the cost?

Solution:

[tex]\to \bold{Cost = 4.3 + 6.89 * \log(length)}[/tex]

In this question, the cost equation increase by 6.89 that is:

[tex]Cost' = 4.3 + 6.89 * \log(length)+6.89\\\\Cost' = 4.3 + 6.89(\log(length) +1)[/tex]

[tex]\therefore \ \log_e \ e=1[/tex]

[tex]\because \\\\Cost' = 4.3 + 6.89( \log(length) + \log_e \ e)[/tex]

Formula:

 [tex]\to \bold{\log(ab)=\log\ a+\log\ b }[/tex]

[tex]\to \bold{4.3+689(\log \ Length *e)}[/tex]

 So, the final answer is "Increase length by e units".

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