Respuesta :

Answer: The empirical formula of the compound is [tex]KMnO_4[/tex]

Explanation:

The empirical formula is the chemical formula of the simplest ratio of the number of atoms of each element present in a compound.

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] ......(1)

Let the mass of the compound be 100 g

Given values:

% of K = 24.7%

% of Mn = 34.76%

% of O = 40.50%

Mass of K = 24.7 g

Mass of Mn = 34.76 g

Mass of O = 40.50 g

To calculate the empirical formula of a compound, few steps need to be followed:

  • Step 1: Calculating the number of moles of each element

We know:

Molar mass of K = 39.10 g/mol

Molar mass of Mn = 54.94 g/mol

Molar mass of O = 16 g/mol

Putting values in equation 1, we get:

[tex]\text{Moles of K}=\frac{24.7g}{39.10g/mol}=0.632 mol[/tex]

[tex]\text{Moles of Mn}=\frac{34.76g}{54.94g/mol}=0.633 mol[/tex]

[tex]\text{Moles of O}=\frac{40.50g}{16g/mol}=2.53 mol[/tex]

  • Step 2: Calculating the mole fraction of each element by dividing the calculated moles by the least calculated number of moles that is 0.632 moles

[tex]\text{Mole fraction of K}=\frac{0.632}{0.632}=1[/tex]

[tex]\text{Mole fraction of Mn}=\frac{0.633}{0.632}=1[/tex]

[tex]\text{Mole fraction of O}=\frac{2.53}{0.632}=4[/tex]

  • Step 3: Writing the mole fraction as the subscripts of each of the element

The empirical formula of the compound becomes [tex]K_1Mn_1O_4=KMnO_4[/tex]

Hence, the empirical formula of the compound is [tex]KMnO_4[/tex]

Eduard22sly

The empirical formula of the compound is KMnO₄

Data obtained from the question

  • Potassium (K) = 24.74%
  • Manganese (Mn) = 34.76%
  • Oxygen (O) = 40.50%
  • Empirical formula =?

How to determine the empirical formula

Divide by their molar mass

K = 24.74 / 39 = 0.634

Mn = 34.76 / 55 = 0.632

O = 40.50 / 16 = 2.531

Divide by the smallest

K = 0.634 / 0.632 = 1

Mn = 0.632 / 0.632 = 1

O = 2.531 / 0.632 = 4

Therefore, the empirical formula of the compound is KMnO₄

Learn more about empirical formula:

https://brainly.com/question/24297883

Otras preguntas