Using distance formula, it is found that the ratio of AC : CB is 2 : 3
What is the distance between two points ( p,q) and (x,y)?
The shortest distance (length of the straight line segment's length connecting both given points) between points ( p,q) and (x,y) is:
D = √[(x-p)² + (y-q)²] units.
Calculate AC and CB using coordinates A (1, 1), B(5, 3), and C(2.6, 1.8) and the distance formula:
AC = √[(2.6 -1)² + (1.8 - 1)²]
AC = √[(1.6 )² + (0.8)²]
AC = 2√(0.8)
Similarly, CB = √[(2.6 -5)² + (1.8 - 3)²]
CB = 3√(0.8)
Therefore, the ratio of AC : CB is 2 : 3
Learn more about distance between two points here:
brainly.com/question/16410393
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