in the diagram find angle mQR

Answer:
[tex]mSQR=1/2m~SR\\[/tex]
[tex]75=1/2m~SR[/tex]
[tex]mSR=150[/tex]
[tex]360=SR+QR+QS[/tex]
[tex]mQR=360-150-133[/tex]
[tex]mQR=77[/tex]
[tex]So, B ~ is ~ your~ answer[/tex]
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hope it helps...
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