Write the standard equation of the circle with center (6,-1) and radius 7.4.

Answer:
C.
Step-by-step explanation:
You do the opposite to the numbers when plugging them into the equation and what they equal will be the radius squared.
6 goes to -6 and -1 turns to 1.
7.4 squared= 54.76
Standard equation of the circle with center (6,-1) and radius 7.4 is [tex](x-6)^{2}+(y+1)^{2} = 54.76[/tex]
Option (C) is correct
"A circle is a round-shaped figure that has no corners or edges. In geometry, a circle can be defined as a closed, two-dimensional curved shape."
"The center of a circle is the point which is equidistant from all points on the circle."
"The constant distance between the center and any point of the circle is called its radius."
We have,
Center (h, k) = (6,-1)
Radius r = 7.4
We know,
Standard equation of the circle is [tex](x-h)^{2}+(y-k)^{2}=r^{2}[/tex]
Substitute the values of h, k, r in standard equation of circle
[tex](x-6)^{2}+(y+1)^{2}=(7.4)^{2}[/tex]
⇒[tex](x-6)^{2}+(y+1)^{2} = 54.76[/tex]
Hence, Standard equation of the circle with center (6,-1) and radius 7.4 is [tex](x-6)^{2}+(y+1)^{2} =54.76[/tex]
∴ Option (C) is correct
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