Answer:
The force of repulsion is 17.802 N
Explanation:
Given;
magnitude of the first charge, q₁ = 8.6 x 10⁻⁶ C
magnitude of the second charge, q₂ = 2.3 x 10⁻⁴ C
distance between the two charges, r = 1 m
The force of repulsion is calculated using Coulomb's law;
[tex]F = \frac{Kq_1q_2}{r^2} \\\\F = \frac{9\times 10^9 \times 8.6\times 10^{-6} \times 2.3\times 10^{-4}}{1^2} \\\\F = 17.802 \ N[/tex]
Therefore, the force of repulsion is 17.802 N
