Taxi company A charges $4 plus $2 per mile. Taxi company B charges $5 plus $3 per mile. Which system best represents this problem?

y = 4 x + 0 . 5 , y = 5x + 0.25

y = 4 + 2x , y = 5+3x

y = 4 x + 1 5 , y = 15x + 2

y = - 0 . 5 x + 4 , y = -0.25x + 5

To solve this, you should convert both rates to equations, with y being the total fare, and x being the number of miles. The rates of both use the format y=mx+b (where m is the amount per mile and b is the flat rate, or original rate).

By subbing in the values for m and b, you get y=2x+4 for A and y=3x+5 for B. This is the second option.

**This question involves writing linear equations, which you may wish to revise. I'm always happy to help!

Taxi company A charges $4 plus $2 per mile. Taxi company B charges $5 plus $3 per mile. Which system best represents this problem? y = 4 x + 0 . 5 , y = 5x + 0.25 y = 4 + 2x , y = 5+3x y = 4 x + 1 5 , y = 15x + 2 y = - 0 . 5 x + 4 , y = -0.25x + 5

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Taxi company A charges $4 plus $2 per mile. Taxi company B charges $5 plus $3 per mile. Which system best represents this problem?

y = 4 x + 0 . 5 , y = 5x + 0.25

y = 4 + 2x , y = 5+3x

y = 4 x + 1 5 , y = 15x + 2

y = - 0 . 5 x + 4 , y = -0.25x + 5