HELP TIMER Write the equation of a hyperbola centered at the origin with x-intercept +/- 4 and foci of +/-2(squareroot 5)

Answer:
[tex]\frac{x2}{a} - \frac{y2}{b2} = 1[/tex]
Step-by-step explanation:
A hyperbola is the locus of a point such that its distance from a point to two points (known as foci) is a positive constant.
The standard equation of a hyperbola centered at the origin with transverse on the x axis is given as:
[tex]\frac{X2}{16} - \frac{b}{4} = 1[/tex]
The coordinates of the foci is at (±c, 0), where c² = a² + b²
Given that a hyperbola centered at the origin with x-intercepts +/- 4 and foci of +/-2√5. Since the x intercept is ±4, this means that at y = 0, x = 4. Substituting in the standard equation:
I don't feel like explaining so...
a. = 4
The foci c is at +/-2√5, using c² = a² + b²:
B = 2
Substituting the value of a and b to get the equation of the hyperbola:
[tex]\frac{x2}{a2} - \frac{y2}{b2} = 1[/tex]
[tex]\frac{x2}{16} - \frac{b2}{4} = 1[/tex]