Simplify: (- sqrt x-4)^2
-X + 4
X-4
2x - 8

The square of [tex](-\sqrt{x-4})[/tex] is (x - 4).
To square a number: just multiply it by itself. A square number is the number we get after multiplying an integer (not a fraction) by itself.
[tex](-\sqrt{x-4} )^{2}[/tex] = [tex](-\sqrt{x-4}) * (-\sqrt{x-4})[/tex] = x - 4
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