Please Big Help!!
Segments AB and CB are tangent to ⨀T. What is the perimeter of ABCT?

Answer:
perimeter is 46
Step-by-step explanation:
Sq(BT) = sq(AT) + Sq(AB)
Sq(17) = Sq(8) + Sq(AB)
So AB = 15
So perimeter of ABCT is 15 + 15 + 8 + 8 = 46
Segments AB and CB are tangent by the Pythagoras theorem, So the perimeter of ABCT is 46 units.
The perimeter of any given figure is the sum of the measure of boundaries of that figure.
Segments AB and CB are tangent.
By the Pythagoras theorem,
[tex](BT)^2 = (AT)^2 + (AB)^2\\(17) ^2= (8) ^2+ (AB)^2[/tex]
So AB = 15
So perimeter of ABCT
= 15 + 15 + 8 + 8
= 46
To learn more about the perimeter click here;
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