Respuesta :

Answer:

[tex] {x}^{2} - 6x + 11 = 0 \\ x = \frac{ - b± \sqrt{ {b}^{2} - 4ac} }{2a} \\ x = \frac{6± \sqrt{ - 8} }{2} \\ x = \frac{6±2i \sqrt{2} }{2} \\ x = 3±i \sqrt{2} [/tex]

Answer:

[tex]x=3\pm\sqrt{2}i[/tex]

Step-by-step explanation:

[tex]x^2-6x+11=0[/tex]

[tex]x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}[/tex]

[tex]x=\frac{-(-6)\pm\sqrt{(-6)^2-4(1)(11)} }{2(1)}[/tex]

[tex]x=\frac{6\pm\sqrt{36-44} }{2}[/tex]

[tex]x=\frac{6\pm\sqrt{-8} }{2}[/tex]

[tex]x=\frac{6\pm2\sqrt{2}i }{2}[/tex]

[tex]x=3\pm\sqrt{2}i[/tex]

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