Find \sin(\beta)sin(β)sine, left parenthesis, beta, right parenthesis in the triangle.
Choose 1 answer:
Choose 1 answer:

(Choice A)
A
\dfrac{15}{8}
8
15

start fraction, 15, divided by, 8, end fraction

(Choice B)
B
\dfrac{8}{17}
17
8

start fraction, 8, divided by, 17, end fraction

(Choice C)
C
\dfrac{8}{15}
15
8

start fraction, 8, divided by, 15, end fraction

(Choice D)
D
\dfrac{15}{17}
17
15

start fraction, 15, divided by, 17, end fraction

Find sinbetasinβsine left parenthesis beta right parenthesis in the triangle Choose 1 answer Choose 1 answer Choice A A dfrac158 8 15 start fraction 15 divided class=
Find sinbetasinβsine left parenthesis beta right parenthesis in the triangle Choose 1 answer Choose 1 answer Choice A A dfrac158 8 15 start fraction 15 divided class=

Respuesta :

Answer:

Its 15/17

Step-by-step explanation:

I did it on Khan

Based on the sine ratio, sin (β) in the right triangle is: D. 15/17.

How to Apply the Sine Ratio?

Where the hypotenuse and opposite side lengths are known, the sine ratio is expressed as, sine β = opposite/hypotenuse.

Given the following:

  • Opposite side = 15
  • Hypotenuse = 17

Applying the sine ratio, we have:

sin β = 15/17

Learn more about the sine ratio on:

https://brainly.com/question/2920412

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