Respuesta :
the answer too your question is 65 it is equal to the square root of 65
Answer:
The absolute value of 4+7i is equal to [tex]\sqrt{4^{2}+7^{2}}[/tex].
The absolute value of the 4+7i be [tex]\sqrt{65}[/tex].
Step-by-step explanation:
The absolute value is given by .
|a + bi| = [tex]\sqrt{a^{2}+b^{2}}[/tex]
Now find the absolute value of the 4+7i.
|4+ 7i|= [tex]\sqrt{4^{2}+7^{2}}[/tex]
|4+ 7i| = [tex]\sqrt{16+49}[/tex]
|4+ 7i| = [tex]\sqrt{65}[/tex]
Therefore the absolute value of the 4+7i is [tex]\sqrt{65}[/tex] .
